Ben Roethlisberger named AFC Offensive Player of the Week

In leading the Steelers to their second consecutive victory, quarterback Ben Roethlisberger was 29-for-45 for 367 yards and four touchdowns, not turning the ball over once.

For that, Roethlisberger was named the AFC's Offensive Player of the Week.

It's the 10th time in Roethlisberger's career he's earned the award, but the first since Week 8 of 2011.

Roethlisberger has thrown for four touchdown passes in two of the team's last three games, and his 34-yard touchdown pass to wide receiver Antonio Brown was the first scoring drive the Steelers have had on their first possession of a game this season.

It's been up-and-down for the franchise quarterback this year. Between multiple turnover games and trade allegations, Roethlisberger has vowed he won't quit on the season or the team. The Steelers have won four of their last six games after an 0-4 start, and sit just one game behind the New York Jets for the AFC's sixth-seed in the playoffs.

More from Behind the Steel Curtain:

• 5 Burning Questions leading into Week 12 vs. Browns
• Will Allen dishes on Cowboys' 'micromanaging' style
• Colts sign Chris Rainey
• Steelers Film Room: Splash plays highlight win
• Steelers didn't change coverage much in second half
• Meet Ray Graham, the newest Steelers roster addition
• Steelers vs. Browns: Tomlin anticipates return of Woodley, Keisel and Foster
• Steelers TE Matt Spaeth to be evaluated this week
• Ben on Tomlin: 'We're not going to sit on this'
• Ray Graham working out for Steelers
• BTSC Week 12 Power Rankings
• A rare Double Renegade leads to two second-half turnovers

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