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Steelers RB Le'Veon Bell named AFC Offensive Player of the Week

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The NFL announced Steelers RB Le'Veon Bell was named the AFC Offensive Player of the Week for his performance in the team's 42-21 victory over the Cincinnati Bengals on Sunday.

Aaron Doster-USA TODAY Sports

Pittsburgh Steelers RB Le'Veon Bell received the AFC Offensive Player of the Week award for his performance in the Steelers' 42-21 victory over the Cincinnati Bengals in Week 14.

Bell totaled 235 yards from scrimmage in the victory by rushing for 185 yards, receiving for 50 yards and scoring three touchdowns on the day (two rushing, one receiving). Bell became only the second player in NFL history to have over 200 yards from scrimmage in three consecutive weeks - the other player being the great Walter Payton.

The last time a Steelers RB earned the Offensive Player of the Week award was Rashard Mendenhall after his Week 6 performance in 2011 against the Jacksonville Jaguars.

The award will certainly serve as a springboard for Bell not only being considered as a first-team All Pro, but also for his first trip to the Pro Bowl. In only his second year, Bell has shown he might be the most complete running back in the NFL.

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